00:01
So continuing on with organic chemistry, we're going to try our hand at some problem solving here.
00:04
So we will try and identify some unknowns.
00:08
So given the molecular formula that we have c5h1002, what we can calculate is the double bond equivalents.
00:20
That is one.
00:22
So therefore we have one double bond in our structure.
00:29
So from the protein nmr, we have a three hydrogen environment triplet at about one ppm, meaning that the methyl group attached to the methylene group.
00:43
We also have a two -proton environment triplet at 2 .35 ppm, meaning that one end of the ch2 group is attached to the methyylene group.
00:55
And lastly, the signal at 2 .35 ppm indicates that one of the ends of the ch2 group is attached to the carbonyl.
01:03
Also from the proton animal, we have a two hydrogen environment sextantile...