Question
A concave lens of focal length $\mathrm{f}$ forms an image which is n times the size of the object. What is the distance of the object from the lens?(A) $(1+\mathrm{n}) \mathrm{f}$(B) $(1-\mathrm{n}) \mathrm{f}$(C) $[(1-\mathrm{n}) / \mathrm{n}] \mathrm{f}$(D) $[(1+\mathrm{n}) / \mathrm{n}] \mathrm{f}$
Step 1
Step 1: The lens formula for a concave lens is given by: \[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \] where \(v\) is the image distance, \(u\) is the object distance, and \(f\) is the focal length of the lens. Show more…
Show all steps
Your feedback will help us improve your experience
Prem Bijarniya and 91 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A concave lens of focal length $F$ produces an image equal to $1 / n$ of size of object, the distance of the image, from the lens is (A) $(n+1) F$ (B) $(n-1) F$ (C) $\left(\frac{n+1}{n}\right) F$ (D) $\left(\frac{n-1}{n}\right) F$
A concave mirror of focal length $\mathrm{f}$ produces an images n times the size of the object. If the image is real then What is the distance of the object from the mirror? (A) $(\mathrm{n}+1) \mathrm{f}$ (B) $[(\mathrm{n}-1) / \mathrm{n}] \mathrm{f}$ (C) $(\mathrm{n}-1) \mathrm{f}$ (D) $[(\mathrm{n}+1) / \mathrm{n}] \mathrm{f}$
A convex lens of focal length $f$ produces a real image $x$ times the size of an object, Then what is the distance of the object from the lens? (A) $(\mathrm{x}+1) \mathrm{f}$ (B) $(\mathrm{x}-1) \mathrm{f}$ (C) $[(\mathrm{x}+1) / \mathrm{x}] \mathrm{f}$ (D) $[(x-1) / x] f$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD