00:01
We all know that the magnification of the mirror is given by m is equal to d i minus f by f which is equal to minus di i by d not.
00:12
The mirror equation can be given by one by f is equal to one by d not plus one by d i f is the focal and di is the position of the image d not is the position of the object now going forward and here i can write the value of f m1 is equal to minus 2 and the value of m2 is equal to minus 3.
00:37
M1 is magnification observed at initial point and m2 is magnification observed at final point.
00:46
If d -i -1 is the position of the image when object is at first location, then i can write a expression as just look at it carefully.
00:56
M1 is equal to plus d -i -1, my, my, and i -1 is equal to plus d -i -1, my minus f by f.
01:05
So just putting the value of m1 here minus 2 is equal to di1 minus f by f on solving it further i get the value of the i 1 is equal to minus f now if di2 is the position of the image when the object is at second location then i can write the expression as m2 is equal to di2 minus f by f on simplification and i can write the value of minus 3 is equal to di2 minus f by f.
01:40
On solving it, finally i get the value of di2, di2 is equal to minus 2f...