Question
A concave mirror has a radius of curvature of $14 \mathrm{~cm}$. If a pointlike object is placed $9.0 \mathrm{~cm}$ away from the mirror on its principal axis, where is the image ?
Step 1
We know that the radius of curvature is twice the focal length, so we can write this as $R = 2f$. Substituting the given value of $R$ into this equation gives us $14 = 2f$. Solving for $f$ gives us $f = 7 \mathrm{~cm}$. Show more…
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