Question
A concave mirror of focal length $20 \mathrm{~cm}$ forms an virtual image having twice the linear dimensions of the object, the position of the object will be $\mathrm{cm}$(A) $7.5$(B) $-10$(C) 10(D) $-7.5$
Step 1
The magnification is defined as the ratio of the image distance, $v$, to the object distance, $u$, with a negative sign for a concave mirror. Therefore, we have $m = -\frac{v}{u}$. Show more…
Show all steps
Your feedback will help us improve your experience
Mirza Aslam Beig and 84 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A concave mirror of focal length 15 cm forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be (a) 22.5 cm (b) 7.5 cm (c) 30 cm (d) 45 cm
The focal length of a concave mirror is 50cm. Where an object be placed so that its image is two times and inverted (a) 75 cm (b) 72 cm (c) 63 cm (d) 50 cm
A concave mirror has a focal length $30 \mathrm{~cm}$. The distance between the two position of the object for which image size is double of the object is (A) $30 \mathrm{~cm}$ (B) $15 \mathrm{~cm} \quad \overline{\text { (C) }-25 \mathrm{~cm}}$ (D) $-15 \mathrm{~cm}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD