Question
A concave mirror of focal length f produces a real image $\frac{1}{\mathrm{n}}$ th of the size of the object placed transverse to the principal axis. The distance of the object is(a) $\mathrm{nf}$(b) $\frac{\mathrm{f}}{\mathrm{n}}$(c) $(1+n) f$(d) $\left(1+\frac{1}{n}\right)$ f
Step 1
For a real image formed by a concave mirror, the magnification is also equal to the negative ratio of the image distance (v) to the object distance (u). This can be written as: \[m = -\frac{v}{u}\] Show more…
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