Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉Join our Discord!

Oh no! Our educators are currently working hard solving this question.

In the meantime, our AI Tutor recommends this similar expert step-by-step video covering the same topics.

Like

Report

Numerade Educator

Like

Report

Problem 59 Easy Difficulty

A conducting rod of length $\ell$ moves on two horizontal frictionless rails, as in Figure $\mathrm{P} 20.30 .$ A constant force of magnitude 1.00 $\mathrm{N}$ moves the bar at a uniform speed of 2.00 $\mathrm{m} / \mathrm{s}$ through a magnetic field $\overrightarrow{\mathrm{B}}$ that is directed into the page. (a) What is the current in an $8.00-\Omega$ resistor $R ?(\mathrm{b})$ What is the rate of energy dissipation in the resistor? (c) What is the mechanical power delivered by the constant force?

Answer

a. 0.5 A
b. 2.00 \mathrm{W}
c. 2.00 \mathrm{W}

Discussion

You must be signed in to discuss.
Top Physics 102 Electricity and Magnetism Educators
Elyse G.

Cornell University

Andy C.

University of Michigan - Ann Arbor

Farnaz M.

Other Schools

Meghan M.

McMaster University

Physics 102 Electricity and Magnetism Bootcamp

Lectures

Join Bootcamp

Video Transcript

{'transcript': "the magnetic force on the road is given by F Is he going toe? I out Be an emotional MF Absolute is equal to be out times the velocity v So the current I we know is defined as absolute are and this is be out really over the resistance are and so we could rearrange and find expression for the magnetic For your b b is equal to i r over and out be so from here we can calculate it be magnetic force is equal to I squared Oh, times are over our V Indians with some simplification and rearranging we get the current high is equal to square root off the magnetic force Yes, be temper speed V over the resistance order and these values are known So that's the spirit hooked off one Newton and speed off to me Just a second over given resistance H bones and hence we get a current zero boring fires MPs Next, the rate at which energy is delivered to the resistor is the power and this power peak is equal to I squared. Times are the square off the current 10 resistance. We know the current to be 0.5 piers that squid multiplied by the resistance. Off it goes once we get in power off to once, finally, for a constant force, power is equal to the dot product off its force, the rust. And this is equal to one. You, too, that is two meters, but second, since they both in the same direction and instigated power again off to what's"}

University of Kwazulu-Natal
Top Physics 102 Electricity and Magnetism Educators
Elyse G.

Cornell University

Andy C.

University of Michigan - Ann Arbor

Farnaz M.

Other Schools

Meghan M.

McMaster University

Physics 102 Electricity and Magnetism Bootcamp

Lectures

Join Bootcamp