A conducting rod $P Q$ of length $4 \ell$ is rotated about a point $O$
in a uniform magnetic field $\mathrm{B} \rightarrow \mathrm{PO}=\ell$ Then
(a) $\mathrm{V}_{\mathrm{Q}}-\mathrm{V}_{\mathrm{P}}=-\left[\left\{\mathrm{B} \omega \ell^{2}\right\} /\right.$
$\{2\}] \quad$ (b) $\mathrm{V}_{\mathrm{Q}}-\mathrm{V}_{\mathrm{O}}=(5 / 2) \mathrm{B} \operatorname{co} \ell^{2}$
(c) $\mathrm{V}_{Q}-\mathrm{V}_{\mathrm{O}}=(9 / 2) \mathrm{B} \omega \ell^{2}$
(d) $\mathrm{V}_{\mathrm{P}}-\mathrm{V}_{\mathrm{Q}}=4 \mathrm{~B} \omega \ell^{2}$