Question
A conductor in the form of a right angle $A B C$ with $A B=3 \mathrm{~cm}$ and $B C=4 \mathrm{~cm}$ carries a current of $10 \mathrm{~A}$. There is a uniform magnetic field of $5 \mathrm{~T}$ perpendicular to the plane of the conductor. The force on the conductor will be(A) $1.5 \mathrm{~N}$(B) $2.0 \mathrm{~N}$(C) $2.5 \mathrm{~N}$(D) $3.5 \mathrm{~N}$
Step 1
Step 1: The force on a conductor carrying current in a magnetic field is given by the formula $F = BIL$, where $B$ is the magnetic field, $I$ is the current, and $L$ is the length of the conductor. Show more…
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