00:02
Okay, so in the problem 16 we have a uniform conductor actually conductor with uniform radius so let's put here the radius of the conductor 1 .2 centimeters so imagine that our conductor is this cylinder here okay, so this cylinder here is our conductor and the radius is in here.
00:32
Okay, so we have this conductor and we know that he carries a current, so let's call this i equals 3 ampers.
00:48
And we have, this current is produced by an electric field of 120 volts per meter.
01:00
So the electric field of 120 volts per meter.
01:12
And the problem just wants to know what is the resistivity of the material.
01:18
Remember that resistivity usually are represented by the greek letter ho.
01:26
So the resistivity of the material also has an equation.
01:30
And we can say that ho, equation, is going to be.
01:35
The resistance of the material, not resistivity, times the cross -sectional area divided by the length of the material.
01:47
So let's remember that first of all, cross -sectional area for a cylinder is just pi r square...