A conservative force F is in the +x-direction and has magnitude F(x) = a/(x + x0)^2, where α= 0.

step 1 Problem 7 .61. We have a force in the X direction. It's inversely proportional to x plus an offs

A conservative force F is in the +x-direction and has...

A conservative force $\overrightarrow{F}$ is in the $+x$-direction and has magnitude $F(x) = a/(x + x_0)^2$, where $\alpha = 0.800$ N $\cdot$ m$^2$ and $x_0 = 0.200$ m. (a) What is the potential-energy function $U(x)$ for this force? Let $U(x) \rightarrow 0$ as $x \rightarrow \infty$. (b) An object with mass $m = 0.500$ kg is released from rest at $x = 0$ and moves in the $+x$-direction. If $\overrightarrow{F}$ is the only force acting on the object, what is the object's speed when it reaches $x = 0.400$ m?

A conservative force $\overrightarrow{F}$ is in the $+x$-direction and has magnitude $F(x) = a/(x + x_0)^2$, where $\alpha = 0.800$ N $\cdot$ m$^2$ and $x_0 = 0.200$ m. (a) What is the potential-energy function $U(x)$ for this force? Let $U(x) \rightarrow 0$ as $x \rightarrow \infty$. (b) An object with mass $m = 0.500$ kg is released from rest at $x = 0$ and moves in the $+x$-direction. If $\overrightarrow{F}$
is the only force acting on the object, what is the object's speed when it reaches $x = 0.400$ m?

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