00:01
Okay, everyone, so today we'll be looking at question 26 from chapter 8.
00:07
And honestly, this is more of a math question than anything.
00:10
It says you have a conservative force.
00:13
Okay, we have a conservative force, and that is equal to 6 .0x minus 12.
00:20
All right, newton's.
00:24
Well, it wants to know, the conservative force where x is in meters, x on a particle moving along the x -axis.
00:32
So the potential energy, u is associated with this force, is assigned a value of 27 joules when x is equal to zero.
00:39
And a wants to know if we can write an expression for you as a function of x, with u in joules and x in meters.
00:48
Write an expression for you.
00:51
Okay.
00:53
Well, this is very simple.
00:55
All we have to do is integrate this.
00:57
So, all right.
01:00
So if we integrate 6 .6x minus 12, if we integrate it, what do we get? well, you do 6x, you add.
01:13
So it will be to the second degree, and you divide by 2 minus 12, you add an x.
01:20
And we know that since it's equal to 27 when x is equal to 0, all you have to do is plus 27.
01:32
And this is it.
01:33
So you is equal to 3x squared minus 12x plus 27.
01:40
That is the answer for a.
01:43
Very simple.
01:44
All you have to do is integrate the conservative force given to you.
01:48
And now b wants to know what is the maximum positive potential energy? well, all we do is set.
01:58
Your conservative force equal to zero...