Question
A constant current of $1.50 \mathrm{amp}$ is passed through an electrolytic cell containing a $0.10 M$ solution of $\mathrm{AgNO}_{3}$ and a silver anode and a platinum cathode until $2.48 \mathrm{~g}$ of silver is deposited.a. How long does the current flow to obtain this deposit?b. What mass of chromium would be deposited in a similar cell containing $0.10 M \mathrm{Cr}^{3+}$ if the same amount of current were used?
Step 1
We know that the molar mass of silver is $107.9 \, \text{g/mol}$, so we can use this to convert the mass of silver into moles: \[2.48 \, \text{g Ag} \times \frac{1 \, \text{mol Ag}}{107.9 \, \text{g Ag}} = 0.02298 \, \text{mol Ag}\] Show more…
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