00:01
Okay in this question a constant force of 2 .5 newton so f is given 2 .50 newton accelerate a stationary particle of mass that is 15 gram through a displacement that is s is given 2 .50 meter okay we have to find out the work done and the average power delivered so work that is force into displacement that is f dot s so when we saw force that is 2 .50 newton multiplied by displacement that is 2 .50 so when we solve it is 6 .25 zool.
00:33
So this will be the answer of work done.
00:36
Okay, now we will go for the power.
00:39
So power is work divided by time, okay? time taken to for the displacement.
00:45
So power that is equal to work divided by time.
00:48
So we have to find out this time.
00:50
So no problem.
00:51
First of all, we know that the final velocity that will be v square equals to u square plus 2 s, okay, and initial velocity u is 0.
00:59
So v square it will be 2a s or we can say we will be root 2 as okay so we have to find out the acceleration okay so acceleration will be f because f equals to m a so f divided by m that will be acceleration so force is 2 .50 newton divided by mass is 15 gram okay and in kilogram it will be 1 ,000 in the numerator so a will be from here 500 divided by 3 meter per second square okay so now we will put the value of a here so from here we will be square root of 2 multiplied by a that is 500 divided by 3 multiplied by s that is from here 2 .50 meter okay so when we solve the final velocity we will get it will be 28 .86 meter per second okay so this is the final velocity okay so we can find out the time from here because v equals to u plus 80 and u is 0 so we will be at.
02:01
So t will be v divided by a.
02:04
And v is given.
02:06
We have found out that this 28 .86...