The specific volume of the water is given as $v_1 = 0.4625 \, \mathrm{m}^3/\mathrm{kg}$. The mass of the water is $m = 0.2 \, \mathrm{kg}$. Therefore, the initial volume of the water is $V_1 = m \cdot v_1 = 0.2 \, \mathrm{kg} \cdot 0.4625 \,
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