00:02
In problem 46, a converging lens has a focal length of 4 .8 centimeters.
00:07
A 1 .5 centimeter high arrow is located 11 centimeters from the lens with the lowest point 4 millimeters above the lens axis.
00:16
Make a full -scale ray tracing diagram to locate both ends of the image and confirm using the lens equation.
00:23
So i'm going to do both.
00:24
It's hard to do a full to scale ray tracing diagram without rulers and a scaled.
00:32
System and i don't have that here on this whiteboard, but i can draw the ray diagram and then we can use the lens equation to see if our answers make sense.
00:42
So our focal length is 4 .8.
00:44
We know the height of the image is, i'm sorry, the height of the object is 1 .5 centimeters, but it's 11 centimeters, so the object distance is 11 centimeters from the lens, but it's 4 millimeters above the lens axis.
01:00
So that's just, that's not really a thing that normally has its own designated value.
01:06
This is four millimeters.
01:07
So i'm going to put that in centimeters.
01:09
That's 0 .4 centimeters.
01:11
So if the object is 1 .5 centimeters high, i'm looking for a point that's 1 .9 centimeters above the surface.
01:21
Or, sorry, above the principal axis.
01:23
So let's just draw the rays in.
01:26
It's hard to draw straight lines here, at least consistently.
01:32
Whoa, there we go.
01:34
And then there's that one.
01:38
In parallel goes out through the focal point.
01:41
In through the focal point comes out parallel.
01:47
Now, i know that's not that good, but our image should be, i'll make it green here.
01:53
The tip of the arrow should be at that point there.
01:56
And we know it's going to be inverted, so it's upside down.
01:59
So then i will do, let's choose red, to do the bottom of the arrow.
02:05
I'm going to go in parallel and then out through the focal point again.
02:14
Oops.
02:15
Let me make that one a little straighter.
02:20
It's still not that straight...