Question
A coolie $2.0 \mathrm{~m}$ tall raises a load of $75 \mathrm{~kg}$ in 25 from the ground to his head and then walks a distance to $40 \mathrm{~m}$ in another 25 . The power developed by the coolie is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$(A) $0.25 \mathrm{kw}$(B) $0.50 \mathrm{kw}$(C) $0.75 \mathrm{kw}$(D) $1.00 \mathrm{kw}$
Step 1
The work done is given by the formula $W = mgh$, where $m$ is the mass of the load, $g$ is the acceleration due to gravity, and $h$ is the height. Substituting the given values, we get $W = 75 \times 10 \times 2 = 1500 \, \text{J}$. Show more…
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