00:01
For this problem, we are going to use these four hafsa reaction reduction potentials.
00:10
They're all from page 709 of the book, table 18 .1.
00:17
So if you put a copper penny in hcl, for the penny to dissolve, copper has to dissociate.
00:26
And it will only dissociate if this reaction here change colors.
00:33
If this reaction here is feasible.
00:35
For the reaction to be feasible, del g has to be negative.
00:40
And since then g is minus nfe, but del g to be negative, e needs to be positive.
00:47
So when we calculate e, which is e cathode minus e anode, or we subtract the reduction potential of the species that is getting oxidized from the reduction potential of the species that is getting reduced, we get minus the reduction potential.
01:03
Minus 0 .334.
01:05
Since this value is negative, it means that this reaction is not feasible and the copper penny will not dissolve in h .c .f...