00:05
For part a, we're asked, what is the composition of copper sulfide? so we have the mass of copper given to us at 2 .196 grams, and we also have the mass of the copper sulfide, which is equal to 2 .748 grams.
00:32
So in this, the percent of copper would be equal to 2 .196.
00:39
Grams over 2 .748 grams times 100%.
00:45
And this would equal 80 % composition of copper.
00:52
And then the percent of sulfur would be 100 % minus 80%, which is equal to 20%.
00:58
Therefore, the percent composition of copper sulfide is 80 % copper and 20 % sulfur.
01:05
For part b, what is the empirical formula? well, we know that the percent composition, if we assume 100 grams of copper sulfide, that means we have 80 grams of copper and 20 grams of sulfur.
01:30
To convert to moles, molar mass of copper is 63 .5 grams in one mole.
01:39
And this would yield 1 .26 moles of copper and molar mass of sulfur is 32 .1 grams in one mole.
01:58
So 20 .0 divided by 32 .1.
02:01
And this is 0 .63.
02:06
Moles of sulfur divided by 0 .623 would give me 1.
02:12
1 .2 .6 .5 .6 .23.
02:15
And 2...