The moment of inertia of a flywheel is given by the formula $I = \frac{1}{2}MR^2$, where $M$ is the mass of the flywheel and $R$ is its radius. Given that $M = 20 \, \text{kg}$ and $R = 25 \, \text{cm} = 0.25 \, \text{m}$, we can substitute these values into the
Show more…