00:01
So given in the question the kinetic energy of the cosmic ray proton entering the atmosphere from space is 2 .0 into 10 to the power 20 electron volt.
00:18
Let it be represented by k.
00:24
So k is 2 .0 into 10 to the power 20 electron volts and it has been asked to find its kinetic energy in joules.
00:33
In the second part if all the kinetic energy of the proton could be harnessed to lift an object of mass 1 .0 kgs near earth's surface the height up to which the object could be lifted and the third is the speed of the proton.
01:11
The third part is the speed of the proton.
01:18
Now we know that 1 electron volt is 1 .6 into 10 to the power minus 19 joules.
01:26
That means 2 .0 into 10 to the power 20 electron volt would be 2 .0 into 10 to the power 20 electron volt times 1 .6 into 10 to the power minus 19 joules per electron volt.
01:36
That comes out to be 32 joules.
01:39
Hence the kinetic energy of the cosmic ray proton is 32 joules.
01:48
Coming to the second part of the question let the height up to which the object could be lifted be h.
02:00
While lifting the object the entire kinetic energy of the proton will be converted into the potential energy of the object.
02:14
The potential energy of the object is mgh.
02:17
The kinetic energy of the proton is k.
02:20
So mgh will be equal to k which is equal to 32 joules...