00:01
Chapter 4, problem 12, we've got a crate, has a net force acting on it, horizontal force acting on it of 140 newtons, and it's got a mass of 32 .5 kilograms.
00:10
We're going to be using two kinematic equations in here because they're asking us to solve for a position in a velocity after 10 seconds.
00:17
But first off, part a really just wants us to find the acceleration of the box.
00:21
Newton's second law, net force is equal to m .a.
00:25
So the force divided by m is going to be our acceleration.
00:30
Is 140, the mass is 32 .5, and that gives us an acceleration of 4 .3 meters per second squared to the right.
00:42
Part b is asking us for how far the box slides after 10 seconds.
00:49
So we're assuming that force is acting for all 10 of those seconds.
00:53
We're going to be using this kinematic equation right here...