A cricket ball of mass $150 \mathrm{~g}$ has an initially velocity $u=(3 \hat{\mathbf{i}}+4 \hat{j}) \mathrm{ms}^{-1}$ and a final velocity $v=(-3 \hat{i}+4 \hat{j}) \mathrm{ms}^{-1}$. After behind hit. The change in momentum (final momentum-initial momentum) is (in $\mathrm{kg} \mathrm{ms}^{-1}$ )
[NCERT|
(a) zero
(b) $-(0.45 \hat{i}+0.6 \hat{j})$
(c) $-(0.9 \hat{i}+1.2 j)$
(d) $-5(\hat{i}+i)$