00:01
Here comes another rather long problem, and we are going to be talking about bomb calorimetry.
00:08
And i just decided to include a picture of one of these just in case you wanted to know a little bit more about what they look like.
00:16
So there's a bomb calorimeter.
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And we're given the following information.
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First, we have a 0 .25 gram sample of benzoic acid.
00:39
And we put it in the bomb calorimeter and undergoes combustion.
00:42
And the temperature changes by 1 .642 degrees c.
00:55
It's combustion, so it increases by 1 .642 degrees.
01:00
And we have 26 .38, our heat of combustion for benzoyic acid equals 26 .38 kilojoules per gram.
01:21
Now, every balm calerometer has a caleromomom.
01:28
Constant, a heat capacity of the caloremeter.
01:31
So we're going to find the heat capacity of the calerrimiter using these values.
01:37
That's our first order of business.
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And it doesn't tell us we need to do this, but i'm telling you we do.
01:46
And to find that, we are going to, that'll be in units of kilojoules per degrees c.
01:56
So we're going to use these values, these three values to find that.
02:01
So the heat capacity, i'm just going to call it.
02:03
Call it heat capacity.
02:08
It's going to be equal to.
02:09
First, let's take our mass.
02:11
I'm going to move this down a little bit to give me some more room.
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We'll be our mass of 0 .235 grams.
02:27
I'm going to multiply that by 26 .38 kilojoules per gram.
02:35
See my grams cancel out.
02:37
And we'll divide that by 1 .642 celsius degrees.
02:43
Do the math on this and i got 3 .78 kilojoules per c degrees.
02:53
And that's my heat capacity of the caloremeter.
02:58
Now, we are also told that we put a, when we switch colors, a 20 .2, i think it's 6, 5 grams of caffeine, which is c8102.
03:34
The molecular formula is burned.
03:38
Our temperature changes by 1 .525 degrees celsius.
03:53
So a says calculate the heat of combustion per mole of caffeine.
04:02
Let's put that in black...