00:01
The coffee and its cooling constant is 0 .09, and the temperature of the surrounding room is 20 degrees.
00:08
How fast is it cooling when its temperature is 80? use linear approximation to find to estimate the change in temperature over the next six seconds.
00:20
And then if it's served at 90 degrees, how long before it's a drinkable 60 degrees? okay, so the first question, how fast is it cooling when its temperature, is 80 is asking you what's dydt when it's 80.
00:36
So dydt is minus k minus .09 time the temperature minus the surrounding temperature.
00:46
So minus .09 times 60, which is minus 5 .4 degrees per second.
00:58
So 5 degrees per second is how fast it's cooling.
01:01
Use linear approximation to estimate the change in temperature over the next six seconds.
01:08
Okay, so here's what they're saying.
01:11
Okay, d, y, d, d, t is approximately equal to y minus y not over x minus x, not.
01:18
Oops, t, sorry...