Question
A current, $I$, in a magnetically coupled circuit satisfies$$20 I+j 100 I=200$$Find the current $I$.
Step 1
The given equation is: $$ 20I + j100I = 200 $$ Show more…
Show all steps
Your feedback will help us improve your experience
Hast Aggarwal and 79 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An electromotive force $$ E(t)=\left\{\begin{array}{ll} 120, & 0 \leq t \leq 20 \\ 0, & t>20 \end{array}\right. $$ is applied to an $L R$ -series circuit in which the inductance is 20 henries and the resistance is 2 ohms. Find the current $i(t)$ if $i(0)=0$.
First-Order Differential Equations
Linear Models
An electromotive force $$E(t)=\left\{\begin{array}{lr}120, & 0 \leq t \leq 20 \\0, & t>20\end{array}\right.$$\ is applied to an $L R$ -series circuit in which the inductance is 20 henries and the resistance is 2 ohms. Find the current $i(t)$ if $i(0)=0$
Modeling with First-Order Differential Equations
The current $I$ through $10 \Omega$ resistor in the circuit given below is (a) $50 \mathrm{~mA}$ (b) $20 \mathrm{~mA}$ (c) $40 \mathrm{~mA}$ (d) $80 \mathrm{~mA}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD