Question
A current of $2.50 \mathrm{~A}$ is passed through a solution of $\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}$ for $2.00 \mathrm{~h}$. What mass of copper is deposited at the cathode?
Step 1
The total charge (Q) can be calculated using the formula Q = It, where I is the current and t is the time. Here, the current (I) is 2.50 A and the time (t) is 2.00 hours. But we need to convert the time from hours to seconds because the unit of current is Ampere Show more…
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