00:01
Okay, guys, we are given the following data for water that is t1 is equal to 100 degree fahrenheit.
00:09
Then we have m is equal to 0 .2 lbm.
00:14
Then we've got v1 is equal to 100 cubic fit.
00:18
And we've got x3 that is equal to 0 .5.
00:22
So from saturated water table f7 .1 corresponding to temperature 100 degree fahrenheit, we can obtain stage 2 specific volume and pressure that is very.
00:32
V2 is equal to vg is equal to 349 .9764 cubic fit per lbm.
00:42
Then we've got p2 is equal to pg and that is equal to 0 .95 lbf divided by insquare.
00:52
So initial specific volume and pressure are equal to wv1 is equal to v1 over m is equal to 100 divided by 0 .2 and that is equal to 500 cubic fit per lbm.
01:11
Then we've got p1 is equal to p2 into v2 divided by v1 is equal to 0 .95 multiplied by 349 multiplied by 9764 4, 349 point.
01:30
It's not multiplied it, it's point.
01:34
9764 divided by 500 and it's equal to 0 .665 lbf per inch square...