Question
A cylindrical specimen of a nickel alloy having an elastic modulus of $207 \mathrm{GPa}\left(30 \times 10^{6}\right.$ psi) and an original diameter of $10.2 \mathrm{mm}$ $(0.40 \text { in. })$ will experience only elastic deformation when a tensile load of $8900 \mathrm{N}\left(2000 \mathrm{lb}_{\mathrm{f}}\right)$is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is $0.25 \mathrm{mm}$ $(0.010 \text { in. })$.
Step 1
In this case, the cross-sectional area of the cylinder is given by $\pi d^2/4$, where $d$ is the diameter. So, the stress $\sigma$ is given by: \[\sigma = \frac{F}{\pi d^2/4}\] Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 68 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa $\left(30 \times 10^{6}\right.$ psi) and an original diameter of $10.2 \mathrm{~mm}(0.40 \mathrm{in}$.) experiences only elastic deformation when a tensile load of $8900 \mathrm{~N}\left(2000 \mathrm{lb}_{\mathrm{f}}\right)$ is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is $0.25 \mathrm{~mm}$ $(0.010 \mathrm{in} .)$
A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa (30\times10^{6 psi) and an } original diameter of $10.2 \mathrm{~mm}(0.40$ in.) experiences only elastic deformation when a tensile load of $8900 \mathrm{~N}\left(2000 \mathrm{lb}_{i}\right)$ is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is $0.25 \mathrm{~mm}$ $(0.010$ in.).
A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa and an original diameter of 10.2 mm (0.40 in.) will experience only elastic deformation when a tensile load of 8900 N (2000 lb ) is applied. Compute the maximum length of the specimen before deformation if the maximum allowable elongation is 0.25 mm (0.010 in.).
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD