A dart is thrown horizontally with an initial speed of $10 \mathrm{~m} / \mathrm{s}$ toward point $P,$ the bull's-eye on a dart board. It hits at point $Q$ on the rim, vertically below $P, 0.19 \mathrm{~s}$ later. (a) What is the distance $P Q ?$ (b) How far away from the dart board is the dart released?