00:03
Okay, so we want to know what the current is the starter and the dead battery is.
00:09
Okay, so the first thing i have to do know is that draw the current.
00:15
So i know that generally current goes from negative to positive.
00:21
Okay, this is for i1.
00:23
Okay, it comes through this point and it's going to divide.
00:27
Okay, i'm going to have i2 from here and and the other one i'm going to call i3.
00:36
Okay, and i'm going to use two rules.
00:43
One is the junction rule.
00:46
You must be familiar with it.
00:49
It tells that the sum of the currents that come in in a junction equals the sum of the current that go out of the junction.
00:59
And the other is the loop rule that tells that the sum of all the potential differences in a closed look was equal to zero.
01:09
So with these two equations, i'm just going to establish two or three equations, okay, to solve the circuit and find the currents.
01:23
Okay, so the first one i'm going to see the junction rule in this point.
01:30
Okay, so you see it's pretty easy.
01:32
It comes current 1 through here and it divides in the current 2 and current 3 okay so remember this is current 3 i just put okay and so i 1 must be equal to i 2 plus i 3 for the junction rule to be 2 be 2 okay so this is the first equation for the other questions i'm going to use the closed loop rule and i'm going to look at two different loops okay the first one is starting at 12 volts from here and is the loop that goes all the way the circuit okay we go back here okay so remember when i take i'm moving uh in the clockwise direction okay so when i measured or take a voltage from minus positive it's positive okay so i start into 12 volts so this is 12 positive okay then i get to the 0 .01 um resistor if you see we are moving in the same direction as the current here so this value must be negative okay the value of the potential difference here and i don't know it exactly but i know on slow that says that voltage equals resistor value times the current.
03:11
Okay, so this is the resistor value 0 .01 times the current and this is i1.
03:20
Okay and then i get to this 0 .06 resistor.
03:25
You see actually this is the same direction as the current so it's negative and is the resistor value times the current that this time is height 3.
03:36
So this will be equal 0, and this is my second equation.
03:41
And the other one i'm going to use dark blue.
03:49
Now i already use that purple.
03:52
Okay, and is this small loop that goes...
03:56
Sorry, i already use purple.
03:59
I'm using this pink.
04:02
I hope it gets different.
04:04
I'm going to take this small loop in the same direction.
04:08
That is a clockwise direction.
04:11
And i start in the 10 volts voltage since it's from negative to positive.
04:19
It's positive.
04:22
And i get to the one arm resistor.
04:24
You can see this is actually positive because it's against the sense of the current.
04:29
So this is one om times i2.
04:33
Okay, and then i have again the 0 .06 resistor that's negative, okay, because i'm taking in the same sense...