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A deep-sea diver should breathe a gas mixture that has the same oxygen partial pressure as at sea level, where dry air contains 20.9% oxygen and has a total pressure of $1.01 \times 10^{5} \mathrm{N} / \mathrm{m}^{2} .$ (a) What is the partial pressure of oxygen at sea level? (b) If the diver breathes a gas mixture at a pressure of $2.00 \times 10^{6} \mathrm{N} / \mathrm{m}^{2},$ what percent oxygen should it be to have the same oxygen partial pressure as at sea level?

(a) $2.12 \times 10^{4} \mathrm{N} / \mathrm{m}^{2}$(b) $1 \%$

Physics 101 Mechanics

Chapter 13

Temperature, Kinetic Theory, and the Gas Laws

Temperature and Heat

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Simon Fraser University

Lectures

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So, given that there is 20.9% oxygen and the total pressure is 1.1 into 10 4 piles, you can't burn meter square compassion. Fisher off oxygen is simply the percentage multiplied by the total picture, so that's 20.9 divided by 100 times 1.0 Wanting to tend bar fight It's turns out to be tool. INDU tend bar four. You can put me just quit. No correspondingly. If you want this partial pressure, it the pressure off who into 10 parts six you 10 per meter squared, which is the clear off the divers mass surrender. So we simply multiplied by. Let's say X is the percentage you might get bloody by X. The percentage on this should be equal to the partial pressure, which is £2. 10 for that is so. This means X is equal don't and minus two, which is a boat one person, which is exactly 1%. Actually, simples that

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