00:01
A dentist is examining a dental filling in a person's tooth.
00:04
The diameter of the filling is 2 .4 millimeters, and the dentist's near point is 17 centimeters.
00:11
To get a better look at the filling, the dentist's on safety goggles fitted with a magnifying glass, which has a focal length of 6 centimeters.
00:19
Find the greatest possible angular size in radiance of the patient's filling when viewed by the dentist with and without the magnifying glass.
00:31
Okay, so for part a, let's start with the angular magnification.
00:42
So the angular magnification is theta prime over theta, where theta is without the magnifying glass, and theta prime is with the magnifying glass.
00:55
But we know that theta is h .o.
00:59
Over n, where h .o is the height of the object, and n is the near point.
01:05
So we have 2 .4 millimeters for ho, and that was given in the problem.
01:19
So we need to convert millimeters to centimeters first.
01:25
So converting 2 .4 millimeters over centimeters because the near point is in centimeters.
01:33
This is 2 .4 millimeters over 17 centimeters to get it into centimeters, we divide by 10, which gives us a theta of 0 .014 radiance.
01:53
So that is for part a...