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# (a) Determine the baryon number of the reaction $\mathrm{p}+\overline{\mathrm{p}} \rightarrow 2 \gamma .$ Determine (b) the baryon number and (c) the electron-lepton number of the reaction $\Omega^{-} \rightarrow \Lambda^{0}+\mathrm{K}^{-}$

## (a)The nuclear reaction is given as follows:$p+\overline{p}=2 \gamma$Count on the left for baryon number:$B=(1)+(-1)$$=0Count on the right for baryon number:B=2(0)$$$=0Therefore, the Baryon number is zero.(b)The nuclear reaction is given as follows:$\Omega^{-} \rightarrow \Lambda^{0}+K^{-}$Count on the left for baryon number:$B=+1$Count on the right for baryon number:$B=(+1)+(0)$Therefore, the Baryon number is zero.(c)The elementary particles Omega $\left(\Omega^{-}\right),$ Lambda $\left(\Lambda^{0}\right),$ and antiparticle of Kaon $\left(\mathrm{K}^{-}\right)$ are notleptons.The nuclear reaction is given as follows:$\Omega^{-} \rightarrow \Lambda^{0}+\mathrm{K}^{-}$Count on the left for electron-lepton number:$L_{\mathrm{e}}=0$Count on the right for electron-lepton number:\begin{aligned} L_{\mathrm{e}} &=(0)+(0) \\ &=0 \end{aligned}

Nuclear Physics

Particle Physics

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##### Christina K.

Rutgers, The State University of New Jersey

##### Aspen F.

University of Sheffield

### Video Transcript

in this. But go question me. You want toe get the barrel number and that phone numbers off the following two equations. So what first creature? We're gonna find out what it's to bear on number. So protons are periods, so we have a bearing about. Plus one. Anti proton is an anti burial. So yes, a fair number of minus one. Right? And so he told her Berra number on the 11 side sexually. Zero when you write gum ice. Not Abe everyone. So we at zero Beira number. So it is also cereal. Actually, Baron number is zero and it's conserved for both defense. I write site. Awful first equation. I'll take a look at his second equation, or here it's a It's a bit more interesting, right? So the bear a number. All right, So d omega minus is a very on the Sigma Sigma zero is also a bureau on Lambda Zero. Sorry. So very on. So dear I half a barrel number plus one same ones. You also have a bearing about plus one. On the other hand, 40 k on this is a miss on Amazon doesn't have a It's not a very on so it has no bearing on number zero. And so you better number is a key plus one, right for the spirit collection for the electron left on number, that is, we have to find Look a t Lipton's in this case, stay are no left aunts in this particular direction. And so the lepton number must be zero. Thanks. So left on number is zero where a spirit number is post two plus one.

National University of Singapore

#### Topics

Nuclear Physics

Particle Physics

##### Christina K.

Rutgers, The State University of New Jersey

##### Aspen F.

University of Sheffield