Question
(a) Determine the force that a vertical string exerts on a 0.80-kg rock of density of 3300 $kg / m^{3}$ when it is fully submerged in water of density 1000 $kg /m^{3} .(b)$ If the force exerted by the string supporting the rock increases by 12% when the rock is submerged in a different fluid, what is that fluid’s density? (c) If the density of another rock of the same volume is 12% greater, what happens to the buoyant force the water exerts on it?
Step 1
We can use the formula for volume which is mass divided by density. So, the volume of the rock is $V = \frac{m}{\rho_{rock}} = \frac{0.80 \, kg}{3300 \, kg/m^{3}} = 0.000242 \, m^{3}$. Show more…
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(a) Determine the force that a vertical string exerts on a $0.80-\mathrm{kg}$ rock of density $3300 \mathrm{kg} / \mathrm{m}^{3}$ when it is fully submerged in water of density $1000 \mathrm{kg} / \mathrm{m}^{3} .$ (b) If the force exerted by the string supporting the rock increases by $12 \%$ when the rock is submerged in a different fluid, what is that fluid's density? (c) If the density of another rock of the same volume is $12 \%$ greater, what happens to the buoyant force the water excrts on it?
a cube of edge length $L=0.600 \mathrm{~m}$ and mass $450 \mathrm{~kg}$ is suspended by a rope in an open tank of liquid of density $1030 \mathrm{~kg} / \mathrm{m}^{3}$. Find (a) the magnitude of the total downward force on the top of the cube from the liquid and the atmosphere, assuming atmospheric pressure is $1.00 \mathrm{~atm}$, (b) the magnitude of the total upward force on the bottom of the cube, and (c) the tension in the rope. (d) Calculate the magnitude of the buoyant force on the cube using Archimedes' principle. What relation exists among all these quantities?
A rock has mass 1.80 kg. When the rock is suspended from the lower end of a string and totally immersed in water, the tension in the string is 12.8 N. What is the smallest density of a liquid in which the rock will float?
Fluid Mechanics
Buoyancy
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