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(a) Determine the product of the reaction $_{3}^{7} \mathrm{Li}+_{2}^{4} \mathrm{He} \rightarrow ?+\mathrm{n}$

(b) What is the Q value of the reaction?

a. _{3}^{7} L i+_{2}^{4} H e \rightarrow_{5}^{10} B+_{0}^{1} n

b. -2.79 M c V

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Cornell University

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

for number 43 were given this nuclear action. We're supposed to find there the product here, and then find the que vea value. Um, so defense of the product. I can tell I'm because his balance his equation. Basically, I know that a neutron has a massive one, but no charge. So on this side, I have a 789 10 11. Over here, there's one the neutrons. So this must be 10. And for charges on the side, I have five. So here I need five. I look in the periodic table, and I see number five is boron. So there's my other product bore on 10. And now to find the Cuba you I'm looking up in the back and the appendix, The mass of each one of these. The lithium is seven tweet. 016 04 This, um helium four point. Oh, too. 603 This boar own 10.12937 And the neutron 1.8 665 So to get the q value. Basically, I'm gonna add these two and then subtract these two from it to see how much meant the difference. in masks. Um, I do that, but I get a difference of massive negative. Negative point. Oh, 2995 So actually, putting energy into this this is the end of thermic. And this is the master. This is measured and use. All of these were used, so it's atomic mass unit. I'm just gonna convert that to energy equivalents. I know that one. You is the same as 931 0.5 mega electron volts. So use canceled. And my answer is going to be in mega electron volts. It's my answer is negative. 2.7 line mega electron volts.

University of Virginia