00:01
In this problem on the topic of rotation, we have a discus thrower accelerating a discus to a speed of 25 meters per second from rest by spinning it through 1 .25 revolutions.
00:11
If the discus moves on the arc of a circle 1 meter in radius, we want to find the final angular speed of the discus, the magnitude of its angular acceleration, and the time rather to accelerate from 0 to 25 meters per second.
00:35
So firstly, the angular speed of the discus omega is equal to the linear speed v over r.
00:42
And this is equal to the speed of 25 meters per second divided by the radius of the arc, which is one meter, which gives the angular speed to be 25 radians per second.
01:07
For part b, we want to find the angular acceleration of the discus.
01:12
Now using an angular equation of motion, we have the final angular speed omega f squared is equal to the initial angular speed omega i squared plus two times the angular acceleration alpha times delta theta, which means the angular acceleration is omega f squared minus omega i squared over two delta theta...