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A diver on a diving board is undergoing simple harmonic motion. Her mass is 55.0 $\mathrm{kg}$ and the period of her motion is 0.800 s. The next diver is a male whose period of simple harmonic oscillation is 1.05 $\mathrm{s}$ . What is his mass if the mass of the board is negligible?

$m_{m}=94.75 \mathrm{kg}$

Physics 101 Mechanics

Physics 103

Chapter 16

Oscillatory Motion and Waves

Periodic Motion

Wave Optics

Rutgers, The State University of New Jersey

University of Washington

Simon Fraser University

Hope College

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

06:50

A diver on a diving board …

01:56

Suppose a diving board wit…

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01:49

A diving board oscillates …

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So we know that the equation for the period she is gonna be going to pi multiplied by the square root of the mass over the ah over the spring. Constant. We know that. Then the period is directly proportional to the square root of the mass. And so we can then say T's of one over T's of two is going to be equal in the square root of M someone over himself to solving for EMS. Up to this would be equal to M Step one multiplied by t's up to over T's of one quantity squared. Then we confined the mass of the male diver. This would be 55 kilograms multiplied by 1.5 seconds, divided by point 800 seconds. Quantity squared. This is equaling 94.7 kilograms and this would be our final answer. That is the end of the solution. Thank you for watching

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