Question
A diverging lens has a focal length of $-25 \mathrm{~cm} . \quad$ (a) Find the image distance when an object is placed $38 \mathrm{~cm}$ from the lens. (b) Is the image real or virtual?
Step 1
(a) We are given the focal length f = -25 cm and the object distance do = 38 cm. Plugging these values into the lens formula, we get: 1/(-25) = 1/38 + 1/di To solve for di, we can first find a common denominator for the fractions: -38/(-25*38) = 25/(25*38) + Show more…
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