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A doubly charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separated by 2.00 cm. What is the electric field strength between the plates?

$E=8.00 \times 10^{5} \mathrm{V} / \mathrm{m}$

Physics 102 Electricity and Magnetism

Chapter 19

Electric Potential and Electric Field

Electric Charge and Electric Field

Gauss's Law

Electric Potential

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University of Sheffield

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

02:41

A double charged ion is a…

00:49

What electric potential di…

01:10

What is the strength of th…

00:45

A voltmeter reads $400 \ma…

00:33

The electric field intensi…

13:17

A uniform electric field o…

03:59

Two parallel conducting pl…

05:16

$\bullet$ A uniform electr…

08:03

00:55

A potential difference of …

04:50

Two large, parallel conduc…

0:00

01:56

The electric field strengt…

02:47

Two large metal parallel p…

03:18

The electric field stren…

02:32

A uniform electric field e…

01:07

What is the electric field…

00:38

01:57

A 12 V battery is connecte…

05:26

A pair of oppositely charg…

so to solve this question, we need to find out potential difference first, because we are about to find out electric field strength. And it says that the charged particle was accelerated between two parallel conducting plates. So we are going to use this equation in the end that is still to be divided by the so we know D. But we don't know be off potential difference. So let's try to find that potential difference were also given the energy that is equal to 32 killer electrons void that is 32 times 10 power three Electron boat on DDE so you can convert this to Jews by multiplying it by electronic charge that his 1.6 times 10 per wonder that in 19. So let's try toe right down formula for you. You in terms of charge and potential difference is given by a Q B. So potential difference V is equal to you, divided by King. So I don't need to convert this to Jules yet because then I can use something to simplify it. So let's say 32 times 10 Power three. So, as I said, if I multiply you this family here by electronic charge e minus or just e. I shall get the value in June. So let's do that. Let's just keep me here. So I'm not going to write all the values to Jews here on DDE. There is one more information given to us that the charge is doubly charged. Particle is doubly charge. That means it has two times the electronic judge. So now you see, I can just cancel the skis out so I can technically find out the value off you in terms of a jewel here. But I don't need to, because equation is already simplified enough. So from this, we can find out we as 16 times 10 power, three bullet. No, this is the information we need to be substitute to substitute in this equation one. So let's call this equation one. So hee is equal to I read about it, buddy, which is equal to 16 times 10 power three divided by the separation distances. Two centimeters. That is 0.2 meters. Remember that you should keep all the values in terms off standard units. So 16 times sympathy. So see this. This is two times 10 power. Negative too. So it will be eight times £10.5 Newton for Coolum. Oh, Julie. Sorry. Vote per meter. So that's the electric field. Also remember that all the values in the beginning were given three significant digits, So keep the values 8.0 times 10. Pal, if I

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