00:03
This is the answer to chapter 10, problem number 43 from the smith organic chemistry textbook.
00:10
And this problem says, draw the structure of 1e4r -1 -4 dimethyl cyclodecene, and then draw the anantimer and name it, including its ez and rs prefixes, and then draw two diasteremeres and name them, including the ez and rs prefixes.
00:28
Okay.
00:30
So if you don't know, you will now, the way to draw a cyclodecane is to draw two fused six -membered rings, but they're not fused.
00:44
So what do i mean by that? so what i mean is you act as if you were going to draw two -fused six -membered rings, but then you omit the point where they would be fused.
01:01
Just like this, cyclodecane.
01:06
And of course, this is cyclodecine.
01:08
So let's put the double bond here, which is going to make this carbon number one.
01:14
So we'll put a methyl group there.
01:17
And then we need a methyl group at carbon number four, and we need it to be in the r designation.
01:25
And so to do that, that's going to be on the dash.
01:32
And hydrogen will be on the wedge.
01:37
And let's just double check.
01:40
So the top, the carbon that leads to the double bond would be priority one.
01:47
The bond pointed down here would be priority two.
01:52
And the methyl group would be priority three.
01:56
And so if we switch the carbon, if we switch the methyl group in the hydrogen in our heads, that the methyl group is dashed.
02:05
And then count priorities would be going counterclockwise.
02:10
So that's s.
02:12
But we switched it.
02:13
So we have to switch the designation.
02:14
So that's r.
02:15
Okay.
02:16
Yes.
02:16
So this is the 4r version.
02:22
Okay.
02:23
So then next, we're asked to draw the anantimer here.
02:27
And so in order to do that, all we have to do is draw the exact same thing.
02:33
But but that methyl group is going to be switched now.
02:37
There we go.
02:42
So like this and like this.
02:52
We'll put the hydrogen there...