Question
a. Draw three segments of the polymer that is formed from 1,4 -polymerization of 1,3 -butadiene in which all the double bonds are trans.b. Draw three segments of the polymer that is formed from 1,2-polymerization of 1,3-butadiene.
Step 1
It is a four carbon compound with double bonds between the first and second, and third and fourth carbons. The structure can be represented as CH2=CH-CH=CH2. Show more…
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Draw a segment of a polymer (containing three monomers) that forms from anionic polymerization of the compound shown below.
Draw the structure of a two-repeat-unit portion of the polymer chain formed from the addition polymerization of 2,3-dimethyl-1,3-butadiene. The monomer 2,3-dimethyl-1,3-butadiene is a derivative of butadiene. The monomer butadiene and a two repeat unit portion of polybutadiene is shown below. 2,3-dimethyl-1,3-butadiene polymerizes in the same manner, but substitutes methyl groups in the 2 and 3 positions.
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