Question
A drill starts from rest. After 3.20 s of constant angular acceleration, the drill turns at a rate of 2628 rad/s.a. Find the drill's angular acceleration.b. Determine the angle through which the drill rotates during this period.
Step 1
After a time (t) of 3.20 seconds, the drill is turning at a rate of 2628 rad/s, which is the final angular velocity (ω). We are asked to find the angular acceleration (α), which is the rate of change of angular velocity. We can use the formula for angular Show more…
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A dentist's drill starts from rest. After 3.20 s of constant angular acceleration, it turns at a rate of 2.51 X 10^4 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period. .
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