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So we're going to be looking at problem 40 from chapter 5 of the physics 5th.
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The question says, a driver's manual states that a driver traveling at 48 kilometers now and desiring to stop as quickly as possible travels 10 meters before the foot reaches the brake.
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The car travels an additional 21 metres before coming to rest.
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From part a, what is the coefficient of friction assumed in these calculations? and for part b, what is the minimum radius for turning a corner of 48 kilometers per route? the first step is, of course, to convert from a kilometers per hour to kilometers per hour to meters per second.
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And we do this by multiplying by a thousand over 3 ,600 here.
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So we get 13 .3 meters per second.
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Then we're going to use a standard cvat equation, v squared is equal to u squared plus 2 s, and we're going to rearrange for a...