Question
A drop of water of mass $m=0.4 \mathrm{~g}$ is placed between two clean glass plates, the distance between which is $0.01 \mathrm{~cm}$. Find the force of attraction between the plates. Surface tension of water $=0.01 \mathrm{~N} / \mathrm{m}$.
Step 1
The pressure difference between the inside and outside of the water drop is given by $\Delta P = P_{\text{inside}} - P_{\text{outside}} = \frac{2T}{r}$, where $T$ is the surface tension of water. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the attraction force between two parallel glass plates, separated by a distance h = 0.10 mm, after a water drop of mass m = 70 mg was introduced between them. The wetting is assumed to be complete.
Calculate the force required to separate the glass plates of area 10^-2m^2 with a film of water 0.05 mm thickness between them (surface tension of water = 70 × 10 ^− 3 N / m ) =70×10^-3N/m))
A thin film of water of thickness $80.0 \mathrm{pm}$ is sandwiched between two glass plates and forms a circular patch of radius $12.0 \mathrm{~cm} .$ Calculate the normal force needed to separate the plates if the surface tension of water is $0.072 \mathrm{~N} / \mathrm{m}$.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD