Question
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of $0.50 \mathrm{~s}$, and the top-to-bottom height of the window is $2.00 \mathrm{~m}$. How high above the window top docs the flowerpot go?
Step 1
We know the total time the pot is in view is 0.50 seconds, and it spends equal time going up and down. So, we divide the total time by 2 to find the time spent in front of the window. \[ t = \frac{0.50s}{2} = 0.25s \] Show more…
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A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of $0.50 \mathrm{~s}$, and the topto-bottom height of the window is $2.00 \mathrm{~m}$. How high above the window top does the flowerpot go?
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of $0.50 \mathrm{~s}$, and the top-to-bottom height of the window is $2.00 \mathrm{~m}$. How high above the window top does the flowerpot go?
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