## 8700 \mathrm{Bq}

### Discussion

You must be signed in to discuss.
##### Christina K.

Rutgers, The State University of New Jersey

##### Andy C.

University of Michigan - Ann Arbor

LB
##### Aspen F.

University of Sheffield

### Video Transcript

for number 18. We have a sample of Tunisia. MME that has a activity. Oh, one point went to his time forthe back row and the half life is 6.5 hours. We want to know how much what the activity is after. Um, two hours. So this is the original activity. Well, I like to use this equation. It's, um it's for the number of boom nuclear you have in your sample. But your number of nuclear that is proportional to, well, the activity. So I'm just going to use that equation. But for activity, it works. This little n is the number of half life's until I don't have ah, about 1/3 of 1/2 life here. So I'm looking for the activity. The original activity was 1.1 times 10 to the fourth. It'll be time to 1/2 raised to the number of half lives. So that's gonna be too or six point of five. And I get 8.7 time. Send the third That girl's

University of Virginia
##### Christina K.

Rutgers, The State University of New Jersey

##### Andy C.

University of Michigan - Ann Arbor

LB
##### Aspen F.

University of Sheffield