00:01
In this problem, we would like to know the mass of sodium hydroxide and the mass of chlorine that can be obtained from 15 liters of a .35 molar solution of sodium chloride.
00:12
So first, we can go ahead and find the moles of sodium chloride that we have present in our solution.
00:19
We have our molar concentration, which can be broken up in two moles per liter.
00:27
And we also know that we have 15 liters.
00:29
So by doing that multiplication, we find that there are 5 .25 moles of sodium chloride present in our solution.
00:41
And we can look up here at our chemical equation to figure out through stochialometry how many moles of cl2 and naoh we have.
00:54
So for cl2, we know that for every two moles of nacl, we require one mole of cl2.
01:15
And so if we divide our number of moles of nacl by 2, we end up with 2 .63 moles of cl2 that can be produced.
01:33
Repeating that same step for our sodium hydroxide.
01:47
So we know that for every two moles of our sodium chloride, we have two moles of sodium hydroxide...