00:01
We are asked to write one or more appropriate lewis structures for the nitrite ion.
00:06
We're also asked to do a couple more things, but we'll do one thing at a time.
00:11
So the nitrite ion, let's go ahead and do our how many we need, how many we have, and do our calculations.
00:17
Electrons we need, electrons we have.
00:20
There are three atoms, one n, two oxygens, each needing eight.
00:26
So we need eight times three, 24 electrons.
00:31
How many do we have? we have five plus and then oxygen is six times two.
00:41
Plus, since it's got a minus one charge, we've got another one.
00:45
It's got 12, 13.
00:47
We have 18 electrons.
00:49
If we subtract this, we get 6 divided by 2 equals 3, which means we're going to be having a double single bond scenario...