(7.29) is given by:
$$\int_{0}^{t} \frac{dt}{\sqrt{1 - \frac{2GM}{c^2r}}}$$
To evaluate this integral, we can make a substitution. Let's define:
$$u = \frac{2GM}{c^2r}$$
Then, we have:
$$du = -\frac{2GM}{c^2r^2}dr$$
Rearranging, we get:
$$dr =
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